Cobol Foro - [Componente] Rutina Números Aleatorios

Hola:

Nunca lo probé, pero a lo mejor esta función te sirve.

Cita:

RANDOM Function
This function returns a pseudo random value from uniform distributions.
Format
FUNCTION RANDOM [(argument-1)]
Argument
1. The type of argument-1 must be integer.
2. The value of argument-1 must be zero or a positive integer. It is used to
generate a pseudo-random string.
3. The RANDOM function with argument-1 will generate a pseudo-random string
using argument-1 as source.
4. If argument-1 is omitted in the RANDOM function first executed in the run unit, a
pseudo-random string is generated using zero as source.
5. When determining a random value from the same pseudo random string after
execution of the RANDOM function, argument-1 may be omitted. The value of
argument-1 is valid until the next RANDOM function having argument-1 appears.
Function Value
1. The function value is any value in the current pseudo-random string.
2. The range of the function value is:
0 ≤ function value < 1
3. If the value of argument-1 (source value) is the same as in a previous execution,
the same pseudo-random string is used.

Saludos.

Fito...

 ENVIRONMENT     DIVISION.
 DATA            DIVISION.
 WORKING-STORAGE SECTION.
 01  Misc.
     05  Pseudo      Pic X.
     05  Multi-Digit Pic 999999999V9(6).
     05  Two-Digit   Pic 99999999.
     05  Vary        Pic 99.  
     05  hora        Pic 99999999.
 PROCEDURE       DIVISION.
 
 Return-Pseudo.
     ACCEPT HORA FROM TIME
     Compute Multi-Digit = (Function Random (hora)) * 1
     Display Two-Digit  " VARY" Vary " -----1--> " Multi-Digit  " --------> " hora  
     Perform Varying Vary from 1 by 1
       Until Vary > 50
        Compute Multi-Digit = (Function Random) * 1
        Move Multi-Digit to Two-Digit
     Display Two-Digit  " VARY" Vary " --------> " Multi-Digit  " --------> " hora  
     End-Perform